Carbon monoxide is detected in air samples by its reaction with diiodine pentoxide to form carbon dioxide and elemental iodine: CO+I2O5 --> CO2+I2. Balance the equation.
Why did the carbon monoxide go to therapy? Because it needed to find balance in its equation with diiodine pentoxide! So, let's help it out.
The balanced equation is:
2 CO + I₂O₅ → 2 CO₂ + 2 I₂
Now, the equation is feeling a lot more balanced, just like the CO molecule after finding some equilibrium!
To balance the equation:
CO + I2O5 --> CO2 + I2
First, count the number of atoms for each element on both sides of the equation:
For Carbon (C):
On the left side, there is 1 carbon atom in CO, and on the right side, there is 1 carbon atom in CO2.
For Oxygen (O):
On the left side, there is 1 oxygen atom in CO, and on the right side, there are 2 oxygen atoms in CO2.
For Iodine (I):
On the left side, there are 5 iodine atoms in I2O5, and on the right side, there are 2 iodine atoms in I2.
Now, we can balance the equation step-by-step:
Step 1: Balance Iodine (I)
On the left side, there are 5 iodine atoms, which means we need 5 iodine atoms on the right side to balance it. To do this, we place the coefficient 5 in front of I2 on the right side:
CO + I2O5 --> CO2 + 5I2
Step 2: Balance Oxygen (O)
On the left side, there is 1 oxygen atom, and on the right side, there are 10 oxygen atoms (2 from CO2 and 8 from the 5I2). To balance it, we place the coefficient 5 in front of I2O5 on the left side:
5CO + I2O5 --> CO2 + 5I2
Step 3: Balance Carbon (C)
On the left side, there are 5 carbon atoms (5 from CO), and on the right side, there is 1 carbon atom (from CO2). To balance it, we place the coefficient 5 in front of CO on the right side:
5CO + I2O5 --> 5CO2 + 5I2
Now, the balanced equation is:
5CO + I2O5 --> 5CO2 + 5I2
To balance the equation, we need to ensure that the number of each atom on the left side of the equation is equal to the number of atoms on the right side. Here's how to balance the equation:
Step 1: Count the number of each atom on both sides.
On the left side of the equation, we have:
1 carbon (C)
1 oxygen (O)
1 iodine (I)
On the right side of the equation, we have:
1 carbon (C)
2 oxygen (O)
2 iodine (I)
Step 2: Balance the atoms one at a time.
Since there is only 1 carbon atom on both sides of the equation, it is already balanced.
Step 3: Balance the oxygen atoms.
On the left side, we have 1 oxygen atom, while on the right side, we have 2 oxygen atoms. To balance the oxygen atoms, we need to add a coefficient of 2 in front of the CO2 on the right side of the equation:
CO + I2O5 → 2CO2 + I2
Step 4: Balance the iodine atoms.
On the left side, there is 1 iodine atom, while on the right side, there are 2 iodine atoms. To balance the iodine atoms, we need to add a coefficient of 2 in front of the I2 on the left side of the equation:
CO + I2O5 → 2CO2 + 2I2
Now the equation is balanced. The final balanced equation is:
CO + I2O5 → 2CO2 + 2I2