is this rigth
HC2HO2+NH4OH-->NH4C2H3O2+H2O
If you changed the vinegar on the left to HC2H3O2. most folks write it as
H CH3COO
thank to u i see the thing i did wrong thank sooooooooo very much
To determine if the chemical equation you provided is balanced, we need to check if the number of each type of atom is the same on both sides of the equation.
The balanced equation should be:
HC2HO2 + NH4OH → NH4C2H3O2 + H2O
To balance this equation, we need to make sure that the number of each type of atom is equal on both sides. Let's count the atoms present in each compound:
On the left side:
- HC2HO2: 1 hydrogen (H), 2 carbon (C), 2 oxygen (O)
- NH4OH: 4 hydrogen (H), 1 nitrogen (N), 1 oxygen (O)
On the right side:
- NH4C2H3O2: 9 hydrogen (H), 1 nitrogen (N), 2 carbon (C), 3 oxygen (O)
- H2O: 2 hydrogen (H), 1 oxygen (O)
Now, let's balance the equation:
HC2HO2 + NH4OH → NH4C2H3O2 + H2O
Since the hydrogen and oxygen atoms are not balanced, we need to adjust the coefficients in front of the compounds:
2 HC2HO2 + 2 NH4OH → NH4C2H3O2 + 2 H2O
Now, let's count the atoms again:
On the left side:
- 2 HC2HO2: 2 hydrogen (H), 4 carbon (C), 4 oxygen (O)
- 2 NH4OH: 8 hydrogen (H), 2 nitrogen (N), 2 oxygen (O)
On the right side:
- NH4C2H3O2: 8 hydrogen (H), 1 nitrogen (N), 2 carbon (C), 3 oxygen (O)
- 2 H2O: 4 hydrogen (H), 2 oxygen (O)
Now, the number of each type of atom is balanced on both sides of the equation. Therefore, the balanced equation is:
2 HC2HO2 + 2 NH4OH → NH4C2H3O2 + 2 H2O