In a contest the prizes were to be $100 for the first place, $50 for second and $20 for the third. Instead, there was 2-way tie for the first place and one third place. If each first prize is twice the value of the third place award, how much did each first place prize winner received?
Do you have the data correct?
2 * $20 = $40
However, it would have been more equitable to give $75 for each first prize winner.
I hope this helps.
Maths
To solve this problem, let's break it down step by step.
We are given that the first prize is $100, the second prize is $50, and the third prize is $20. We are also told that there was a 2-way tie for the first place and one third place.
Let's denote the value of the third place award as "x". According to the problem, each first prize winner received twice the value of the third place award.
Since there was a 2-way tie for the first place, the two winners both received twice the value of the third place award. Therefore, the amount each first place winner received is 2x.
Now, we can set up an equation to represent the total prize money distributed:
2x + 2x + x = 100 + 50 + 20
Simplifying the equation:
5x = 170
To solve for x, we divide both sides of the equation by 5:
x = 170 / 5
x = 34
Therefore, the value of the third place award (x) is $34.
Since each first prize winner received twice the value of the third place award, they each received 2 * $34 = $68.
So, each first place prize winner received $68.