given
x=t^2 and y=t-2
find a relationship between x amd y( express y in terms of x)
is the relationship a function
solve each for t, then set these results equal to each other.
You will have an equation containing only x's and y's and constants. .
X=t^2, y =t - 2, t =square røot of x. Y + 2 =t . Y + 2 =square root of x . But since u want it to be lyk dis ax +by = 2. . Y - square root of x = -2
To find a relationship between x and y, let's substitute the given expression for x into the equation for y.
Given:
x = t^2
y = t - 2
We'll solve the equation for t in terms of x:
x = t^2
Taking the square root of both sides, we get:
√(x) = t
Now we substitute this value of t into the equation for y:
y = (√(x)) - 2
So, the relationship between x and y is y = (√(x)) - 2.
To determine if this relationship is a function, we need to check if each x-value has a unique corresponding y-value. In other words, for every x, there can only be one y. In this case, the equation y = (√(x)) - 2 represents a function since each value of x will correspond to a unique value of y.