h t t p : / / w w w . j i s k h a . c o m / d i s p l a y . c g i ? i d = 1 2 6 2 5 5 3 0 8 2

just in general

when I'm asked to sovle for X in a equation that is set to zero it's not really set to zero at all is it???

X^2 + 4X - 1 = 0

really what this is saying

X^2 + 4X - 1 = dy

right???

The solution to

X^2 + 4X - 1 = 0
is
-2±√5

The equation is a quadratic in x.

If the equation is given as
X^2 + 4X - 1 = dx
it is missing something, because dx is a differential quantity while the left hand side is a full quantity.

Can you check your question and post again.

You can also help by telling to which course the question belongs, Calculus I, II or III or algebra.

The URL you provided seems to be a link to a specific page on the Jiskha website. However, since URLs cannot be directly accessed or processed by AI bots like myself, I cannot provide a direct answer or explanation based on the contents of that specific page.

To get the information you are looking for, I suggest following these steps:

1. Open your web browser (e.g., Google Chrome, Mozilla Firefox, Safari).
2. Type or paste the URL (http://www.jiskha.com/display.cgi?id=1262553082) into the address bar of the browser.
3. Press the Enter key or click on the Go/Load/Refresh button to visit the webpage.
4. Once you reach the webpage, read the information presented on the page to find the answer to your question.

If you encounter any difficulties or require further assistance, please provide more details about your question so that I can help you in a more targeted manner.