At the distance of the earth from the sun the pressure exerted by sunlight is avout 10^-5 Pa How much force does this pressure exerted on 10m^2 array of solar cells on a satellite when the array is perpendicular to the direction of the sunlight? If the satellite has a mass of 200kg, what acceleration does this force give?

Please do not post the same question more than once. One does not get instant responses here.

can you help any further so i understand?

dont be a jerk man, its not like everyone is smart

See my response to your original post.

Austin/Angel,

Please have some respect for people who help you!
Also, please watch your language, we have students of all ages here.
MM

To calculate the force exerted by the pressure of sunlight on the solar array, we can use the formula:

Force = Pressure × Area

Given:
Pressure = 10^-5 Pa
Area = 10 m^2

Substituting the values in the formula, we get:

Force = (10^-5 Pa) × (10 m^2)
= 10^-5 × 10
= 10^-4 N

Hence, the force exerted by the pressure of sunlight on the solar array is 10^-4 N.

To calculate the acceleration that this force gives to the satellite, we can use Newton's second law of motion:

Force = Mass × Acceleration

Given:
Force = 10^-4 N
Mass = 200 kg

Rearranging the formula, we get:

Acceleration = Force / Mass

Substituting the values, we have:

Acceleration = (10^-4 N) / (200 kg)
= 5 × 10^-7 m/s^2

Therefore, the force exerted by the pressure of sunlight on the solar array is 10^-4 N, and the acceleration it gives to the satellite is 5 × 10^-7 m/s^2.