At the distance of the earth from the sun the pressure exerted by sunlight is avout 10^-5 Pa How much force does this pressure exerted on 10m^2 array of solar cells on a satellite when the array is perpendicular to the direction of the sunlight? If the satellite has a mass of 200kg, what acceleration does this force give?
The force F = (radiation pressure)x(area)
a = F/m
can you help any further i really don't understand..
Do you understand thet Force equals pressure times area?
Have you heard of Newton's second law?
Force = (mass) x (acceleration)
That is as well as I can explain it.
To calculate the force exerted by the pressure of sunlight on the solar cell array, we'll use the formula:
Force = Pressure * Area
Given that the pressure exerted by sunlight is 10^-5 Pa and the area of the solar cell array is 10m^2, we can substitute these values into the formula:
Force = (10^-5 Pa) * (10m^2)
Calculating this, we get:
Force = 10^-5 * 10 = 10^-4 N
Therefore, the force exerted on the solar cell array is 10^-4 Newtons.
To find the acceleration resulting from this force on the satellite, we can use Newton's second law of motion:
Force = Mass * Acceleration
Given that the mass of the satellite is 200kg and the force exerted on the solar cell array is 10^-4 N, we can rearrange the formula to solve for acceleration:
Acceleration = Force / Mass
Substituting the values:
Acceleration = (10^-4 N) / (200 kg)
Calculating this, we get:
Acceleration = 5 * 10^-7 m/s^2
Therefore, the acceleration resulting from the force exerted on the satellite is 5 * 10^-7 meters per second squared.