# MATHS

1) given that x= log(small5)3 + log(small5)4, find algebraically the value of x

2)a mug of tea cools according to the law T(small t)= T(small 0)e to the power^-kt where T(small 0) is the initial temp and T(small c)is the temp after t minutes. all temps are in celciius.

a) a particular mug of tea is cooled from 100*C to 75*C in a quater of an hour. therefore clculate value of k.

b) by how many degrees will the temperature of this tea fall in the next quater of an hour.

1. 👍 0
2. 👎 0
3. 👁 201
1. you want log5(12)
x = log5 (12)
or
5^x = 12
log10 (5^x) = log10 (12) = 1.0792
or
x log10 (5) = log10 (12) = 1.0792
x (.699) = 1.0792
x = 1.0792/.699

1. 👍 0
2. 👎 0
2. 2)a mug of tea cools according to the law T(small t)= T(small 0)e to the power^-kt where T(small 0) is the initial temp and T(small c)is the temp after t minutes. all temps are in celciius.

Tt = To e^(-kt)

a) a particular mug of tea is cooled from 100*C to 75*C in a quater of an hour. therefore clculate value of k.

75 = 100 e^-(.25k) if t in hours and not minutes
.75 = e^-.25k
ln .75 = -.25k
k = -.288/-.25

b) by how many degrees will the temperature of this tea fall in the next quater of an hour.

T = 75 e^-1.15 (.25)
I will leave that to you

1. 👍 0
2. 👎 0
3. thanks alot damon ...i luv u!!!!

1. 👍 0
2. 👎 0

## Similar Questions

1. ### Trigonometry

This is a logs question If u=x/y^2, which expression is equivalent to log u? 1) log x + 2 log y 2) 2(log x- log y) 3) 2(log x + log y) 4) log x- 2 log y

asked by Charles on February 11, 2012
2. ### Trigonometry

The expression log(x^n/ radical y)is equivalent to 1. n log x - 1/2 log y 2. n log x- 2 log y 3. log (nx) - log (1/2y) 4. log (nx) - log (2y)

asked by Stephen on February 11, 2012
3. ### Algebra 2

How is the expression log 32 - log 8 written as a single logarithm? log 4 log 8 log 24 log 40

asked by Sandra on February 13, 2016
4. ### Math

If ln a=2, ln b=3, and ln c=5, evaluate the following: (a) ln(a^−2/b^4c^−3)= -.9524 (b) ln(√b^−4*c^1*a^−1)= -1.739 (c) ln(a^2b^4)/ln(bc)^−2= 42.39 (d) (ln(c^−1))*(ln(a/b^3))^−4= -.03507 I am getting these answers

asked by Banana on August 22, 2018

Which of the following expressions is equal to log (x sqrt-y)/z^5 A. log x + log (1/2) + log y– log 5 – log z B. log [x + (1/2)y – 5z] C. log x + (1/2)log y – 5 log z d. [(1/2) log x log y]/(5 log z)

asked by Katrina on August 3, 2009
1. ### Calculus AB

How do you solve a system of logarithmic equations? They have completely different bases: {(log(25)^3)x + (log(2)^7)y = log(5)^27 {(log(7)^8)x + (log(3)^5)y = log(49)^2

asked by Carmen on July 29, 2016
2. ### Algebra 2

how do not understand how to do this Log X + Lob (X-3) = 1 I know I do this Log X(X-3)=1 then I do this Log X^(2) - 3X = 1 then I do this 2 Log (X-3X) = 1 then 2 Log (-2X) = 1 then (2 Log (-2X) = 1)(1/2) Log (-2X) = 1/2 then (Log

asked by HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!! on February 25, 2009
3. ### college algebra

Write expression as one logarithm and simplify if appropriate. log 3√x + log x^4 - log x^3 4 log (x+3) - 5 log (x^2+4) + 1/3 log y I have these who problems but I don't know where to start. HELP Please.

asked by Deb on April 17, 2013
4. ### Algebra 2

-Explain the difference between log base b (mn) and ( log base b of m)(log base b of n). Are they equivalent? My answer: Let b=2, m=8, n=16 *log base b (mn)=log base b of m + log base b of n log base 2 of 8+ log base 2 of 16=7 *

asked by Anonymous on July 21, 2013
5. ### math

Calculate without using tables or calculators log 450 and log 324 given log 2 =0.3010 and log 3 =0.4771

asked by John Makotamo on March 14, 2013
6. ### chem

this is my question Calculate the hydronium ion consentration and the hydroxide concentration in blood in which the PH is 7.3. I don't have invlog on my calculator so I hit log(7.3)= .863 for hydronium. Is this dumb for me to do?

asked by Jon on March 23, 2007