A weightlifter raises a 90k-g barbell from the floor to a height of 2/2 m in 0.6 s. What was his average power output during his lift?
Sorry I wrote it wrong the first time!
90k-g barbell from the floor to a height of 2.2 m in 0.6 s
g=acceleration due to gravity=9.8 m/s^sup2;
Work done
=F.D
= 90g * 2.2
= 1940 N-m
Power (W, N-m/s, or J/s)
= 1940 J /0.6 s
= 3234 W
Note: one horsepower = 746 watts
M=90kg
h=2.
time=0.6sec
g=9.8m/sec
Power=w/t
=f.h/t ( w=f.h)
=m.g.h/t (f=m.g)
=90×9.8×2/0.6
=3234watt
To calculate the average power output of the weightlifter during the lift, we can use the formula:
Average Power = Work Done / Time
First, let's find the work done. The work done is equal to the force applied multiplied by the distance traveled. In this case, the force applied by the weightlifter is equal to the weight of the barbell:
Force = Mass × Acceleration due to gravity
Note that the weight in this case is mass multiplied by acceleration due to gravity. The mass of the barbell is given as 90 kg.
Acceleration due to gravity, denoted as "g," is approximately 9.8 m/s^2.
So, the weight of the barbell is:
Weight = Mass × Acceleration due to gravity
= 90 kg × 9.8 m/s^2
Next, we need to calculate the distance traveled by the barbell. The height the barbell was raised is given as 2/2 meters.
Now we can calculate the work done:
Work Done = Force × Distance
= Weight × Distance
Finally, we can calculate the average power using the work done and the given time (0.6 seconds):
Average Power = Work Done / Time
Plug in the values to get the average power output of the weightlifter during the lift.