# Physics

A stone that starts at rest is in free fall for 8.0 s.

a.Calculate the stone's velocity after 8.0 s.

b. What is the stone's displacement during this time?

Given:
t = 8.0 s
a = 9.81 m/s^2

For a, in order to calculate the velocity, should i use d = vit + 1/2 at^2 and only use the 1/2 at^2.

For b, should i use the d = vit + 1/2at^2 to calculate the distance.

Thanks I appreciate this a lot

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1. v = Vo + a t
v = 0 + 9.81 (8)

d = Vo t + (1/2)(9.81)(64)
= 0 +4.9(64)

so yes, you have the right idea.

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