DQ sells 6 times as many orders of french fries as sonic everyday. If both sold 60 more orders DQ would only sell 3 times as many fries. How many do each sell before and after the incease?

math - DrBob222, Wednesday, December 23, 2009 at 4:34pm
S = number FF Sonic sells.
D = number FF DQ sells.
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D = 6S every day.
If each sells 60 more, then
D + 60 = 3(S + 60) or
D + 60 = 3S + 120 or
D = 3S + 120
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The two equators are as follows:
D = 6S
D = 3S + 120
Solve these two simultaneous equation for D and S (before the addition of 60), then add 60 to each to determine the number sold after adding 60 to each. Post your work if you get stuck.

math - petie, Thursday, December 24, 2009 at 9:14am
Where did the 120 come from?

The 120 came from a multiplication error.

3(S + 60) = 3S +180

I hope this helps.

PsyDAG is correct. I made two errors but they corrected each other; the final two final equations to solve simultaneously are correct.


If each sells 60 more, then
D + 60 = 3(S + 60) or
D + 60 = 3S + 120 or This should be
D + 60 = 3S + 180 which leads to
D = 3S + 120 and that is the same as the original. I was thinking faster than I was writing.

D = 3S + 120

The 120 comes from the equation D + 60 = 3(S + 60).

To understand where it comes from, let's break down the problem:

We are given that DQ sells 6 times as many orders of french fries as Sonic every day. So, we can say that D = 6S.

Next, we are told that if both DQ and Sonic sold 60 more orders, DQ would only sell 3 times as many fries. This can be represented by the equation D + 60 = 3(S + 60). Here, D + 60 represents the number of fries DQ sells after the increase, and S + 60 represents the number of fries Sonic sells after the increase.

Now, let's simplify the equation D + 60 = 3(S + 60):
Expand to get: D + 60 = 3S + 180
Subtract 180 from both sides to isolate the terms:
D - 120 = 3S
Rearrange to get: D = 3S + 120

So, D = 3S + 120 represents the number of fries DQ sells before the increase, and D + 60 = 3(S + 60) represents the number of fries DQ sells after the increase.

To solve for the values of D and S, you need to solve these two simultaneous equations. Once you find the values of D and S before the increase, you can add 60 to each to determine the number sold after adding 60 to each.

If you need further assistance or steps to solve the simultaneous equations, please let me know.