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Calculus  derivatives of e
Find an equation of the tangent line to the graph of y = e^(−x^2) at the point (5, 1/(e^25)). My work: y' = 2xe^(x^2) y' when x = 5 = 10e^25 y  (1/e^25) = 10e^25 * (x  5) y = (10e^25) (x  5) + (1/e^25) This is incorrect.
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Use the Substitution method to solve the system of equations. y  2x = 5 3y  x = 5 Solve one of the equations for x or y. Let's solve the first one for y: y  2x = 5 y = 2x  5 Now let's substitute 2x  5 for y in the second
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