find the slope and the y-intercept of the line. write fractional answer in the lowest terms.
4y+9x+3=11+9x
the slope is?
the y-intercept is (0,?
help im not to good at algebra
put it in this form:
y=mx+b
It is easy to write this in slope intercept form.
y = m x + b
here
9y = 0 x + 8
the slope, m is zero
when x = 0, y = 8/9 (the y intercept)
Since the slope is zero, y = 8/9 for any real x in fact a horizontal line.
To find the slope and y-intercept of the line, we need to rewrite the equation in slope-intercept form, which is in the form of y = mx + b, where m represents the slope and b represents the y-intercept.
Starting with the given equation:
4y + 9x + 3 = 11 + 9x
The first step is to isolate the term with y on one side of the equation:
4y = 11 + 9x - 9x - 3
Now, combine like terms on the right side:
4y = 8
Next, divide both sides of the equation by 4 to solve for y:
y = 8/4
Simplifying the fraction 8/4, we get:
y = 2
Now that we have the equation in slope-intercept form (y = mx + b), we can clearly see that the slope (m) is 0, and the y-intercept (b) is the point (0, 2).
Therefore, the slope is 0, and the y-intercept is (0, 2).