. Give the equation of the line that passes through point (5, 1) and is parallel to the line y = 3x – 1. Please help, I am so confused.
The line passing through (x1,y1) and parallel to y=mx+b
is (y-y1)=m(x-x1)
Substitute (5,1) for (x1,y1) and y=3x-1 for y=mx+b
gives
y-1=3(x-5)
Rerranging
y=3x-14
Check
1=3x-14
1=3(5)-14
1=1 OK