ladder 13 feet long . if she set the base of the ladder on the level ground 5 feet from the side of a houes, how many feet above the ground will the top of the ladder be when it rest against the house?
Isn't this a right triangle?
Pythagorean theorem applies:
13^2=h^2+5^2
Please do not post the name of your school online. Your School Subject is Math.
You can use the Pythagorean theorem: a^2 + b^2 = c^2
5^2 + b^2 = 13^2
To solve this problem, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
In this case, the ladder forms a right triangle with the ground and the side of the house. The ladder itself is the hypotenuse, and the distance from the base of the ladder to the house is one of the other sides. Let's call this distance "a."
From the problem statement, we know that the ladder is 13 feet long and the base of the ladder is 5 feet from the side of the house. So, we have:
Length of the ladder (hypotenuse) = 13 feet
Distance from the base to the house (one side) = 5 feet
Using the Pythagorean theorem, we can calculate the height of the ladder against the house (the other side). Let's call this height "b."
The Pythagorean theorem is written as:
c^2 = a^2 + b^2
where c is the length of the hypotenuse.
Plugging in the known values from the problem:
13^2 = 5^2 + b^2
169 = 25 + b^2
Subtracting 25 from both sides:
144 = b^2
Taking the square root of both sides:
b = √144
b = 12
Therefore, the top of the ladder will be 12 feet above the ground when it rests against the house.