Find the equation of a line that passes through the point (1,2)and has a slope of 1/3. Show how you found the
equation.
I have been sitting here for almost an hour trying to understand this!!
Use the equation y - y1 = m(x - x1) with the point (x1, y1) = (1, 2) and the slope m = 1/3.
y - 2 = 1/3 (x - 1)
Now put the equation in slope-intercept form.
Thank you! I think I'm beginning to get it now!!!
To find the equation of a line that passes through a given point and has a given slope, you can use the point-slope form of a linear equation.
The point-slope form of a linear equation is given by: y - y1 = m(x - x1), where (x1, y1) represents the given point and m represents the slope of the line.
In this case, the given point is (1, 2) and the slope is 1/3.
Now, let's substitute the values into the point-slope form equation:
y - 2 = (1/3)(x - 1)
Next, we can simplify this equation:
y - 2 = (1/3)x - 1/3
To get rid of the fraction, we can multiply the entire equation by 3:
3(y - 2) = 3(1/3)x - 3(1/3)
3y - 6 = x - 1
Finally, let's rewrite the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept:
x - 3y = -5
So, the equation of the line that passes through the point (1, 2) and has a slope of 1/3 is x - 3y = -5.