find k so that the line through
(3,k) is parrallel to 5x - 3y = 2 then find k so that the line is perpendicular to 3x+2y=6
In the first case, the slope must be 5/3.
In the second case, the slope of the original line is -3/2 and the slope of the perpendicular line must be 2/3 (so that the slope product is -1).
Use the requirement that k = y when x = 3 to get the value of the constant term in y = mx + b in both cases.
The same line will not satisfy all requirements.