350 attend a play $3 for adults and $1 dollar for children Admission receipts are $750 how many adults and how many children attende. All I need is the formula and I could figure out the problem I keep taking wrong numbers in order.
Children + adult = total receipts
$1.00(x) +$3.00(350-x) = $750
solve for x=>>>> number of children tickets, 350- "x" =>>>adult tickets
To solve this problem, we can use algebraic equations. Let's denote the number of adults attending the play as 'a' and the number of children attending as 'c'. According to the information given, there were 350 attendees in total.
We know that the admission cost for adults is $3 and for children is $1. The total admission receipts are $750. Using this information, we can set up the following equations:
Equation 1: a + c = 350 (since the total number of attendees is 350)
Equation 2: 3a + 1c = 750 (since the total admission receipts amount to $750)
To solve these equations, we can use the method of substitution or elimination.
Using the method of substitution, we can express 'c' in terms of 'a' by solving Equation 1 for 'c':
c = 350 - a
Now, substitute the value of 'c' in Equation 2:
3a + 1(350 - a) = 750
Simplify the equation:
3a + 350 - a = 750
2a + 350 = 750
2a = 750 - 350
2a = 400
Divide both sides by 2 to solve for 'a':
a = 400 / 2
a = 200
Now, substitute the value of 'a' back into Equation 1 to find the value of 'c':
200 + c = 350
c = 350 - 200
c = 150
Therefore, there were 200 adults and 150 children who attended the play.