my daughter needs help finding a mystery number.

1)when the mystery number is
divided by 3,there is a remainder
of 1.
but it has to be the same thing
over again with 4 remainder 2 and
5 remainder 4.And there is one more
what is the smallest number that
could be divided by the mystery
number.

"when the mystery number is

divided by 3,there is a remainder
of 1"

So, we know that the number must be 1, 4, 7, 10, etc. Each of those numbers n have the property that n modulus 3 = 1. (Modulus is the remainder when a natural number is divided by a natural number).

"n modulus 4 = 2"
This limits the numbers to 2, 6, 10, 14, etc. Note that this also means that the number is even.

"n modulus 5 = 4"
Similarly, this limits the numbers to 4, 9, 14, 19, etc. The number must be a multiple of 5 with 4 added to it.

Let us start with the last condition (as it has the greatest increase) and limit it to evens. Find the first number that satisfies the first two conditions.
4, 14, 24, 34

34 satisfies all the above conditions.

I DO NOT GET WHAT U GUYS ARE SAY BUT I KNOW THE ANSWER

To find the mystery number, we need to look for a number that satisfies the given conditions. Let's break it down step by step:

1) When the mystery number is divided by 3, there is a remainder of 1.

This means the mystery number can be written in the form: 3n + 1, where n is an integer.

2) When the mystery number is divided by 4, there is a remainder of 2.

This means the mystery number can be written in the form: 4m + 2, where m is an integer.

3) When the mystery number is divided by 5, there is a remainder of 4.

This means the mystery number can be written in the form: 5k + 4, where k is an integer.

To find a number that satisfies all three conditions, we need to find a common solution for n, m, and k.

We can start by finding the values of n, m, and k that satisfy each equation separately:

For the first condition (divided by 3 with a remainder of 1):
n can be 0, 1, 2, 3, ...

For the second condition (divided by 4 with a remainder of 2):
m can be 0, 1, 2, 3, ...

For the third condition (divided by 5 with a remainder of 4):
k can be 0, 1, 2, 3, ...

To find the smallest common solution, we need to find the least common multiple (LCM) of 3, 4, and 5.

The LCM of 3, 4, and 5 is 60.

Therefore, the mystery number is 60 + 1 = 61.

To find the smallest number that could be divided by the mystery number, we can divide any number larger than 61 by 61, and the result will always be an integer.

So, the smallest number that could be divided by the mystery number is 61 itself.