Find the [H3O+] in a solution having [OH-] = 8.8x10^-2 M
[H3O+]x[OH-]=1x10^-14
[H3O+]x[8.8x10^-2]=1x10^-14
i am almost sure i am right up to here but i don't know what to do next and i don't have a scientific calculator.. please help!!
Good lord. YOu will not pass Chemistry, nor learn it,without a scientific calculator. Just how do you plan on getting logarithms?
PUt this in your google search window:
1E-14 / 8.8E-2
To find the [H3O+] in a solution when you are given [OH-], you can use the equation [H3O+][OH-] = 1x10^-14, which is known as the ion product of water.
In this case, you have [OH-] = 8.8x10^-2 M. Substituting this value into the equation, you get:
[H3O+][8.8x10^-2] = 1x10^-14
To isolate [H3O+], divide both sides of the equation by 8.8x10^-2:
[H3O+] = (1x10^-14) / (8.8x10^-2)
Now, to simplify this calculation without a scientific calculator, you can use scientific notation and basic arithmetic operations.
First, divide the numerator and the denominator by 10^-2 to convert them into standard numerical forms:
[H3O+] = [(1/10^-14) / (8.8/10^-2)]
Next, simplify the expression:
[H3O+] = [(1/10^-14) * (10^2/8.8)]
Now, you need to multiply 1/10^-14 by 10^2 and divide the result by 8.8:
[H3O+] = (1 * 10^2) / (10^-14 * 8.8)
Since any number divided by 1 is itself, you can remove the denominators:
[H3O+] = 10^2 / (10^-14 * 8.8)
To simplify further, you can multiply 10^2 by 8.8 in the numerator:
[H3O+] = 88 / (10^-14 * 8.8)
Now, you need to multiply 10^-14 by 8.8:
[H3O+] = 88 / (8.8 * 10^-14)
Finally, simplify the expression by dividing 88 by 8.8:
[H3O+] = 10^14
Therefore, the [H3O+] in the given solution is 10^14 M.