an electrical baseboard heater drawws a current of 6.0A and has a potential difference of 240V. For how long must it remain on to use 220 000 J of electrical energy.
The wattage (power)consumed is I*V = 1440 W.
The time required to consume 220,000 J ls 220,000/1440 seconds.
Convert to hours or minutes, if you wish.
To determine how long the electrical baseboard heater must remain on to use 220,000 J of electrical energy, we can use the formula:
Energy = Power x Time
The power of an electrical appliance is given by:
Power = Current x Voltage
We are given that the current (I) of the heater is 6.0 A and the potential difference (V) is 240 V.
Substituting these values into the power equation, we can calculate the power of the heater:
Power = 6.0 A x 240 V
= 1440 W
Now, we can rearrange the energy equation to solve for time:
Time = Energy / Power
Substituting the given energy into the equation:
Time = 220,000 J / 1440 W
Time = 152.78 seconds
Therefore, the electrical baseboard heater must remain on for approximately 152.78 seconds (or about 2 minutes and 32.78 seconds) to use 220,000 J of electrical energy.