Given the fuction y = log3(x+3)+2, calculate the zero of the function. GIve an exact answer.
So you want to set
log3(x+3) + 2 = 0
log3(x+3) = -2
by definition:
3^-2 = x+3
x = 1/9 - 3
x = -26/9
log3(x+3) + 2 = 0
log3(x+3) = -2
by definition:
3^-2 = x+3
x = 1/9 - 3
x = -26/9