A toy car runed off the edge of a table that is 1.225m high. If the car lands 0.400m from the base of the car to fall,
a)how long does it take the car to fall
2(1.225)/-9.80=-0.25=0.5s
b)what is the horizontal velocity of the car?
Actually, the time to fall is
T = sqrt (2H/g).
That seems to be what you did, but you were incorrect in writing
-0.25 = .50
Also since you are measuring distance down, forget the minus sign.
Once you get the time T, use
T = D/Vx to get the horizontal velocity, Vx.
To find the horizontal velocity of the car, we can use the equation:
Velocity = Distance / Time
In this case, the distance the car travels horizontally is 0.400m, and the time it takes to fall is 0.5s.
Therefore, the horizontal velocity of the car is:
Velocity = 0.400m / 0.5s = 0.8 m/s
To calculate the horizontal velocity of the car, we need to use the equation of motion for horizontal motion:
horizontal velocity = horizontal distance / time
From the problem, we know that the horizontal distance is 0.400m and the time is 0.5s. Plugging these values into the equation, we get:
horizontal velocity = 0.400m / 0.5s = 0.8 m/s
So, the horizontal velocity of the car is 0.8 m/s.