A toy car runed off the edge of a table that is 1.225m high. If the car lands 0.400m from the base of the car to fall,

a)how long does it take the car to fall
2(1.225)/-9.80=-0.25=0.5s
b)what is the horizontal velocity of the car?

Actually, the time to fall is

T = sqrt (2H/g).

That seems to be what you did, but you were incorrect in writing
-0.25 = .50
Also since you are measuring distance down, forget the minus sign.

Once you get the time T, use
T = D/Vx to get the horizontal velocity, Vx.

To find the horizontal velocity of the car, we can use the equation:

Velocity = Distance / Time

In this case, the distance the car travels horizontally is 0.400m, and the time it takes to fall is 0.5s.

Therefore, the horizontal velocity of the car is:

Velocity = 0.400m / 0.5s = 0.8 m/s

To calculate the horizontal velocity of the car, we need to use the equation of motion for horizontal motion:

horizontal velocity = horizontal distance / time

From the problem, we know that the horizontal distance is 0.400m and the time is 0.5s. Plugging these values into the equation, we get:

horizontal velocity = 0.400m / 0.5s = 0.8 m/s

So, the horizontal velocity of the car is 0.8 m/s.

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