Give five ordered pairs that makes the equation true y = 20 + x3

find y for each of these

x.....y
0
-1
1
2
-2
3
-3

The problem is actually y = 20 + x/3. Would it still be the same?

To find five ordered pairs that make the equation y = 20 + x^3 true, you can choose random values for x and calculate the corresponding value of y. Here are five examples:

1. Let's choose x = 0:
Substitute x = 0 into the equation:
y = 20 + (0^3)
y = 20 + 0
y = 20
So the ordered pair is (0, 20).

2. Let's choose x = -1:
Substitute x = -1 into the equation:
y = 20 + (-1^3)
y = 20 + (-1)
y = 19
So the ordered pair is (-1, 19).

3. Let's choose x = 1:
Substitute x = 1 into the equation:
y = 20 + (1^3)
y = 20 + 1
y = 21
So the ordered pair is (1, 21).

4. Let's choose x = 2:
Substitute x = 2 into the equation:
y = 20 + (2^3)
y = 20 + 8
y = 28
So the ordered pair is (2, 28).

5. Let's choose x = -2:
Substitute x = -2 into the equation:
y = 20 + (-2^3)
y = 20 + (-8)
y = 12
So the ordered pair is (-2, 12).

These are five examples of ordered pairs that satisfy the equation y = 20 + x^3. You can choose different values of x to find more ordered pairs.