find the product

(2x+1)(3x-2)

6^x2-x-2

sorry I made mistake, the product is

6x^2 -x -2

To find the product of the given expression (2x+1)(3x-2), we can use the distributive property.

First, multiply the first terms of each binomial: 2x * 3x = 6x^2.
Next, multiply the outer terms of each binomial: 2x * -2 = -4x.
Then, multiply the inner terms of each binomial: 1 * 3x = 3x.
Finally, multiply the last terms of each binomial: 1 * -2 = -2.

Now, combine the like terms obtained from the four products:
6x^2 - 4x + 3x - 2

Simplify the expression:
6x^2 - x - 2

Therefore, the product of (2x+1)(3x-2) is 6x^2 - x - 2.