Chemistry

Cyclopropane is converted to propene in a first-order process. The rate constant is 5.4 × 10-2 hr-1. If
the initial concentration of cyclopropane is 0.150 M, what will its concentration be after 22.0 hours?

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asked by Ericka
  1. k=5.4x10^-2
    t=22.0 hours
    initial=0.150 M
    final=?


    ln(x/0.150) = - (5.4x10^-2)(22.0)
    x= 0.127

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    posted by carmen
  2. .0457

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