Parents donated fudge for the Christmas fund raiser for your classroom.40 pounds of chocolate fudge sold for &2.15 per pound and vanilla fudge sold for $1.90 per pound.Your class made $158.20.How many pounds of fudge were sold.
40 * 2.15 = $86 Chocolate fudge
158.20 - 86 = $72.20 Vanilla fudge
72.20 / 1.90 = ? pounds of vanilla fudge
Let's assume the weight of chocolate fudge sold is x pounds, and the weight of vanilla fudge sold is y pounds.
Given that:
x + y = 40 pounds (Total weight of fudge sold)
2.15x + 1.90y = 158.20 dollars (Total amount earned)
We can solve this system of equations to find the values of x and y.
Using the first equation, we can solve for y: y = 40 - x.
Substituting the value of y in the second equation, we get:
2.15x + 1.90(40 - x) = 158.20.
Simplifying this equation:
2.15x + 76 - 1.90x = 158.20,
0.25x = 82.20.
Dividing both sides by 0.25, we get:
x = 328.
Therefore, 328 pounds of chocolate fudge were sold.
Substituting the value of x in the first equation, we get:
328 + y = 40,
y = 40 - 328,
y = -288.
However, negative pounds of fudge are not possible. Therefore, there might be an incomplete or incorrect information provided in the problem. Please double-check the given data or clarify any additional information to proceed further.
To find the number of pounds of fudge sold, we need to set up a system of equations based on the given information.
Let's assume the number of pounds of chocolate fudge sold is represented by 'x' and the number of pounds of vanilla fudge sold is represented by 'y'.
According to the problem, a total of 40 pounds of chocolate fudge was sold at $2.15 per pound, so the equation for the chocolate fudge sales can be written as:
2.15x
Similarly, the equation for the vanilla fudge sales can be written as:
1.90y
Now, we know that the total sales amount for both types of fudge is $158.20, so we can set up the equation:
2.15x + 1.90y = 158.20
Since we don't know the exact values of 'x' and 'y', we need to find a way to express one variable in terms of the other. We can do this by using the information given in the problem that a total of 40 pounds of chocolate fudge was sold:
x + y = 40
Now we have a system of two equations:
2.15x + 1.90y = 158.20 ---(Equation 1)
x + y = 40 ---(Equation 2)
To solve this system of equations, we can use a method called substitution.
Rearrange Equation 2 to solve for x:
x = 40 - y
Now substitute this value of x in Equation 1:
2.15(40-y) + 1.90y = 158.20
Simplify the equation:
86 - 2.15y + 1.90y = 158.20
Combine like terms:
-0.25y + 86 = 158.20
Subtract 86 from both sides:
-0.25y = 72.20
Divide both sides by -0.25:
y = 289.2
Now substitute this value of y back into Equation 2 to find x:
x + 289.2 = 40
Subtract 289.2 from both sides:
x = -249.2
Since it doesn't make sense to have a negative amount of fudge sold, we can conclude that there was an error in the calculations or the given information.
Please verify the information and try again.