the derivative of 2x^e is zero right or no? do i have to use the log formula
2 x^e is x to the power 2.718.. It is not a constant and therefore the derivative is not zero.
Use the formula for the derivative of x to a power that is constant (x^a). The formula for that may involve a log.
Are you sure you did not mean e^x? The derivative of that is not zero either.
Please let us know if you need further help.
I should finish up that last question because I was incorrect in saying the formula involved a logarithm.
The derivative of x^a with respect to x is just a x^(a-1)
so the derivative of 2 x^e is
2e x^(e-1)
If in form of multiplication then (frist)(derivative of second)+(second)(darivative of frist)
To find the derivative of the function 2x^e, we use the power rule of differentiation. The power rule states that if we have a function of the form x^n, where n is a constant, the derivative is found by multiplying the constant by the exponent, and then subtracting 1 from the exponent.
In this case, we have 2x^e, where e is a constant known as Euler's number (approximately 2.718...). Applying the power rule, we multiply 2 by the exponent e, and then subtract 1 from e:
Derivative of 2x^e = 2e * x^(e-1).
So, the derivative of 2x^e is 2e * x^(e-1). It is important to note that since e is a constant, the derivative is not zero.