is this right? I need to write a linear function that fits this data and round to the nearest tenth. In 1991 the life expectancy in males was 68.8 and in 1995 it was 71.9.... and so on. I first got the slope

m= 71.9-68.8 / 4-1 m = 3.1/3
I fit the slope into y-y1 = m(x-x1)
y-68.8 = 3.1/3x- 3.1/3
is the function y = 3.1/3x + 203.3/3 or should I get rid of the fractions please help!
Thanks in advance!

To find the linear function that fits the given data points, you correctly started by finding the slope using the formula: m = (y2 - y1) / (x2 - x1). In this case, (x1, y1) = (1991, 68.8) and (x2, y2) = (1995, 71.9):

m = (71.9 - 68.8) / (1995 - 1991)
m = 3.1 / 4

So far, so good. Now, let's proceed to write the linear function using the slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.

Substituting the slope we found (m = 3.1/4):

y = (3.1/4) x + b

Now, to find the value of b (the y-intercept), we can use one of the given data points (1991, 68.8). Substitute these values into the equation and solve for b:

68.8 = (3.1/4) * 1991 + b
68.8 = 1536.85 + b
b = 68.8 - 1536.85
b ≈ -1468.05

Now that we have the slope (m ≈ 3.1/4) and the y-intercept (b ≈ -1468.05), we can write the linear function as:

y ≈ (3.1/4) x - 1468.05

To get rid of the fractions, we can multiply both sides of the equation by 4:

4y ≈ 3.1x - 4(1468.05)
4y ≈ 3.1x - 5872.2

To round to the nearest tenth, divide both sides by 4:

y ≈ (3.1/4)x - 1468.05/4
y ≈ 0.775x - 367.0125

Therefore, the final linear function that fits the given data points, rounded to the nearest tenth, is approximately:

y ≈ 0.775x - 367.0