A student's grade on an examination was transformed to a z value of 0.67. Therefore, we know that she scored approximately in the top

Look up Z = 0.67 in a table in the back of your statistics text labeled something like "areas under the normal distribution." Since you want to know the proportion that scored that high or higher, that would be in the smaller portion.

I hope this helps.

To determine the position of a score in a distribution, we can use the z-score. A z-score measures the number of standard deviations a score is away from the mean.

In this case, the student's z-value is 0.67. A positive z-score indicates that the student's score is above the mean.

To find the exact position of the student's score in terms of percentile, we need to consult a standard normal distribution table (also known as the z-table) or use a statistical calculator that can calculate percentiles.

1. Using a z-table:
- Look for the row that corresponds to the closest value to 0.67 (in this case, 0.6).
- Look for the column that corresponds to the second decimal place of 0.67 (in this case, 0.7).
- The intersection of the row and column will give you the percentile value.
- Based on the table, a z-score of 0.67 corresponds to approximately 74th percentile.

2. Using a statistical calculator:
- Input the z-score of 0.67 into the calculator.
- The calculator will provide the result of the percentile. In this case, it would be approximately 74%.

Therefore, the student scored approximately in the top 74 percent of the distribution.