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calculus please help!!
Find the range of the function F(x)= definite integral from [6,x] of sqrt(36t^2)dt. [0, 36π] [0, 18π]*** [6, 6] [6, 0]
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consider the function f that is continuous on the interval [5,5] and for which the definite integral 0(bottom of integral sign) to 5(top of integral sign) of f(x)dx=4. Use the properties of the definite integral to evaluate each
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Can someone explain to me how to do these? Given the following definite integral and n=4 answer the following questions. (Round your answers to six decimal places.) 1. Use the Trapezoidal Rule to approximate the definite integral.
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Evaluate lim (1³ +2³ +3³ +…+ n3)/n^4 n →∞ by showing that the limit is a particular definite integral and evaluating that definite integral.
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Evaluate the integral by making the given substitution. (Use C for the constant of integration. Remember to use absolute values where appropriate.) integral x^5/x^65 dx, u = x6 − 5 I got the answer 1/6ln(x^65)+C but it was
asked by Anonymous on February 4, 2020

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Evaluate the following indefinite integral by using the given substitution to reduce the integral to standard form integral 2(2x+6)^5 dx, u=2x+6
asked by vishal on September 10, 2013 
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Note: You can get full credit for this problem by just answering the last question correctly. The initial questions are meant as hints towards the final answer and also allow you the opportunity to get partial credit. Consider the
asked by kitor on January 25, 2014 
Calculus
I have two questions, because I'm preparing for a math test on monday. 1. Use the fundamental theorem of calculus to find the derivative: (d/dt) the integral over [0, cos t] of (3/5(u^2))du I have a feeling I will be able to find
asked by Jennifer on May 9, 2009 
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Integral of: __1__ (sqrt(x)+1)^2 dx The answer is: 2ln abs(1+sqrt(x)) + 2(1+sqrt(X))^1 +c I have no clue why that is! Please help. I used substitution and made u= sqrt(x)+1 but i don't know what happened along the way! Your first
asked by Gabriela on April 20, 2007 
Calculus
The following definite integral gives the area of the region between the graph of the function f(x) = Icosx  x^2I (I=modulus), the xasis, and the lines x=2 and x=2. the integral of mod cosx  x^2 from 2 to 2. Describe a
asked by Alex on May 19, 2015 
Calculus
Would someone clarify this for me... Is antiderivatives just another name for intergral and why is intergral of a function is the area under the curve? Antiderivatives is another word for integral. Why area? THink on this...the
asked by Jan on September 12, 2006
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