Find the result if the sumn of the roots of y= x^2+3x-5 is added to the product of the roots.
The roots are [-3 +/-sqrt29]/2
+1.19258 and -4.19258
The sum of the roots is -3
The product of the roots is
(9/4) - (29/4) = -5
Add them together and you get -8
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To find the sum and product of the roots of a quadratic equation, we can use the formula:
For a quadratic equation of the form ax^2 + bx + c = 0, the sum of the roots is given by:
Sum of roots = -b/a
The product of the roots is given by:
Product of roots = c/a
In this case, the equation is y = x^2 + 3x - 5. Comparing it with the standard form ax^2 + bx + c = 0, we can see that a = 1, b = 3, and c = -5.
Using the formulas above, we can find the sum and product of the roots:
Sum of roots = -b/a = -3/1 = -3
Product of roots = c/a = -5/1 = -5
Now, to find the result if the sum of the roots is added to the product of the roots, we simply add the calculated values:
Result = Sum of roots + Product of roots = -3 + (-5) = -8
Therefore, the result is -8.