The titration of 25.0 mL of an unknown concentration H2SO4 solution requires 83.6 mL of 0.12 M LiOH
solution. What is the concentration of the H2SO4 solution (in M)?

A) 0.40 M B) 0.10 M C) 0.20 M D) 0.25 M E) 0.36 M

The answer is supposedly C, but I got A. What am I doing wrong? I used the formula M1V1=M2V2 and got .250Lx=.836*0.12M.

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  1. M1V1 = M2V2
    M1 = x
    V1= 0.0250L
    M2 = 0.12M
    V2 = 0.0836L
    Substitute in the given values like so;

    0.0250M1 = (0.12M)(0.0836L)

    0.0250M1 = 0.010032mol

    Divide both sides of the equation by the coefficient in front of M1 to solve for it;
    M1 = 0.010032mol / 0.0250L
    M1 = 0.40128M
    So M1 = 0.40M

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  2. Ah scratch my last answer forgot that the mole ratio is 1:2 so you have to divide your M2V2 answer by two then just do the exact same thing as before.

    so, 0.0250M1 = 0.010032mol / 2

    M1 = 0.005016 / 0.0250
    M1 = 0.20

    Alright sorry about that.

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  3. How did u get the mole ratio?

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  4. you need to balance the equation. H2SO4+2LiOH=LiSO4+2H2O. from the balanced equation you can see that the ratio is 1;2

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