The perimeter of a rectangle is 66 m the length is 9m more than twice the width
I am having trouble finding the dimensions
To find the dimensions of a rectangle given its perimeter and the relationship between its length and width, we can set up the following equation:
Perimeter = 2 * (Length + Width)
Let's use this equation to solve the problem.
Given:
Perimeter = 66 m
Length = 9 m + 2 * Width
Substituting the values into the equation:
66 = 2 * (9 + 2 * Width + Width)
Simplifying the equation:
66 = 2 * (9 + 3 * Width)
66 = 18 + 6 * Width
Now, let's isolate the variable:
66 - 18 = 6 * Width
48 = 6 * Width
To solve for Width, divide both sides by 6:
48 / 6 = Width
8 = Width
Now that we have the value of the Width, we can substitute it back into the equation for the Length:
Length = 9 + 2 * Width
Length = 9 + 2 * 8
Length = 9 + 16
Length = 25
Therefore, the width is 8 m and the length is 25 m.
2 w + 2 (2 w + 9) = 66
6 w + 18 = 66
6 w = 48
then L = 2 w + 9