for this question
A bullet is fired from a rifle that is held 1.8 m above the ground in a horizontal position. The initial speed of the bullet is 1120 m/s. Find
why is the equation just (.5)(9.8)(t^2)=1.8
why don't we have to take in account for initial velocity:
(.5)(a)(T^2)+(Vinitial)(T)=(delta distance) ????
Hey, the bullet is not falling in the direction of the initial velocity. The bullet is falling due to gravity, downward, falling for a distance of 1.8 meters.
You do the vertical falling distance to get time in the air, then use that time to calculate how far horizontally the bullet went.