how do you figure out how to Balance H2SO4+pb(OH)4=pb(SO4)2=H20
The unbalanced chemical equation is:
H2SO4 + Pb(OH)4 --> Pb(SO4)2 + H2O
Balancing the SO4 groups (2 of them):
2H2SO4 + Pb(OH)4 --> Pb(SO4)2 + H2O
Balancing the H's (8 of them):
2H2SO4 + Pb(OH)4 --> Pb(SO4)2 + 4H2O
Ah, balancing chemical equations, a classic conundrum. Well, here's my humorous attempt to answer your question:
To balance the equation H2SO4 + Pb(OH)4 = Pb(SO4)2 + H2O, you'll need a delicate touch, like balancing on a unicycle while juggling pineapples. Let's give it a go!
First, we count the number of atoms on each side. Bingo! On the left side, we have 2 Hydrogen (H) atoms, 1 Sulfur (S) atom, and 4 Oxygen (O) atoms. On the right side, we have 1 Lead (Pb) atom, 2 Sulfur (S) atoms, and 4 Oxygen (O) atoms, along with 2 Hydrogen (H) atoms in water.
Now, let's start by balancing the easier elements. We have 2 Hydrogen (H) atoms on the left side but only 2 Hydrogen (H) atoms on the right side. Ta-da! Hydrogen is already balanced.
Next, we move to the Oxygen (O) atoms. On the left side, we have 4 Oxygen (O) atoms, but on the right side, we only have 4 Oxygen (O) atoms in Pb(SO4)2 and 1 Oxygen (O) atom in water. Uh-oh! We need to balance that.
To balance the Oxygen (O) atoms, we'll add a coefficient of 2 in front of H2O. Boom! This will give us 4 Oxygen (O) atoms on the right side as well.
Now, we're left with balancing the Sulfur (S) and Lead (Pb) atoms. On the left side, we have 1 Sulfur (S) atom, but on the right side, we have 2 Sulfur (S) atoms. Oh boy, we need to fix that.
To balance the Sulfur (S) atoms, we'll add a coefficient of 2 in front of H2SO4 on the left side. Fantastic! Now, we have 2 Sulfur (S) atoms on both sides.
Finally, we balance the Lead (Pb) atom. On the left side, we have 1 Lead (Pb) atom, and on the right side, we also have 1 Lead (Pb) atom. Hooray! It miraculously balances itself without any additional efforts.
And voila! The balanced equation is 2H2SO4 + Pb(OH)4 = Pb(SO4)2 + 2H2O. Problem solved! Just remember, balancing equations takes practice, patience, and a pinch of clownish charm.
To balance the chemical equation H2SO4 + Pb(OH)4 = Pb(SO4)2 + H2O, you need to make sure that the number of atoms on both sides of the equation is the same.
Here is a step-by-step process for balancing this equation:
1. Start by counting the number of atoms of each element on both sides of the equation.
H2SO4: 2 H atoms, 1 S atom, and 4 O atoms
Pb(OH)4: 1 Pb atom, 4 O atoms, and 4 H atoms
Pb(SO4)2: 1 Pb atom, 2 S atoms, and 8 O atoms
H2O: 2 H atoms and 1 O atom
2. Start by balancing the atoms that appear in the fewest compounds. In this case, it would be the Pb atoms.
The left side has 1 Pb atom, while the right side has 1 Pb atom, so they are already balanced.
3. Next, balance the sulfur (S) atoms.
The left side has 1 S atom, while the right side has 2 S atoms in Pb(SO4)2, so we need to multiply the H2SO4 molecule by 2:
2H2SO4 + Pb(OH)4 = Pb(SO4)2 + H2O
4. Now, balance the oxygen (O) atoms.
The left side has 4 O atoms, while the right side has 2 O atoms in Pb(SO4)2 and 1 O atom in H2O. Since the right side has fewer O atoms, we need to add coefficients to the H2O molecule:
2H2SO4 + Pb(OH)4 = Pb(SO4)2 + 2H2O
5. Finally, balance the hydrogen (H) atoms.
The left side has 4 H atoms (two from each H2SO4 molecule), while the right side has 4 H atoms from Pb(OH)4. The hydrogen atoms are already balanced.
The balanced equation is:
2H2SO4 + Pb(OH)4 = Pb(SO4)2 + 2H2O
To balance the chemical equation H2SO4 + Pb(OH)4 = Pb(SO4)2 + H2O, let's follow these steps:
Step 1: Count the number of atoms of each element on both sides of the equation.
On the Left Side (Reactants):
- Hydrogen (H): 2
- Sulfur (S): 1
- Oxygen (O): 4
- Lead (Pb): 1
On the Right Side (Products):
- Hydrogen (H): 2
- Sulfur (S): 1
- Oxygen (O): 6 (2 from Pb(SO4)2 and 4 from H2O)
- Lead (Pb): 1
Step 2: Balance the elements one at a time.
Balance the Oxygen (O) atoms:
- There are 4 O atoms on the reactant side and 6 O atoms on the product side.
- To balance the O atoms, add a coefficient of 2 in front of H2O on the reactant side. The equation becomes:
H2SO4 + Pb(OH)4 = Pb(SO4)2 + 2H2O
Balance the Hydrogen (H) atoms:
- There are 2 H atoms on both sides of the equation, so no additional balancing is needed.
Balance the Sulfur (S) atoms:
- There is 1 S atom on both sides of the equation, so no additional balancing is needed.
Balance the Lead (Pb) atoms:
- There is 1 Pb atom on both sides of the equation, so no additional balancing is needed.
Final balanced equation:
H2SO4 + Pb(OH)4 = Pb(SO4)2 + 2H2O