Hi, could anyone help me please, Thank.

Gas in a container is at a pressure of 1.3 atm and a volume of 1.0 m3.
(a) What is the work done on the gas if it expands at constant pressure to twice its initial volume?

(b) What is the work done on the gas if it is compressed at constant pressure to one-quarter its initial volume?

Hey chanley

What up what up what up

Not much not much

atm=576

Sure, I can help you with that. To calculate the work done on a gas during expansion or compression at constant pressure, we can use the formula:

Work = Pressure * Change in volume

Let's break down the problem into two parts and solve them step by step.

(a) The gas is expanding at constant pressure to twice its initial volume.

1. Calculate the change in volume:
Change in volume = 2 * Initial volume - Initial volume
= 2 * 1.0 m^3 - 1.0 m^3
= 1.0 m^3

2. Plug the values into the formula:
Work = Pressure * Change in volume
= 1.3 atm * 1.0 m^3
= 1.3 atm * m^3

So, the work done on the gas during expansion is 1.3 atm * m^3.

(b) The gas is compressed at constant pressure to one-quarter its initial volume.

1. Calculate the change in volume:
Change in volume = 1/4 * Initial volume - Initial volume
= 1/4 * 1.0 m^3 - 1.0 m^3
= -0.75 m^3

Note: The negative sign indicates compression.

2. Plug the values into the formula:
Work = Pressure * Change in volume
= 1.3 atm * (-0.75 m^3)
= -0.975 atm * m^3

So, the work done on the gas during compression is -0.975 atm * m^3.

I hope this helps! Let me know if you have any further questions.