Driving in your car with a constant speed of 12 m/s, you encounter a bump in the road that has a circular cross section. If the radius of curvature of the bump is r = 34 m, find the apparent weight of a 60 kg person in your car as you pass over the top of the bump in Newtons.

weight= mg-v^2/r

so it wud be (60x9.8-12^2)/34??

= 13.06N??

To find the apparent weight of a person in your car as you pass over the top of the bump, we need to consider the normal force acting on the person. The normal force is the force exerted by a surface to support the weight of an object resting on it.

First, let's understand the forces acting on the person as the car passes over the bump. At the top of the bump, there are two forces acting on the person: the gravitational force (weight) and the normal force.

1. Gravitational force (weight): The weight of the person is given by the formula W = m * g, where m is the mass of the person and g is the acceleration due to gravity (approximately 9.8 m/s²). In this case, the person's weight is W = 60 kg * 9.8 m/s².

2. Normal force: The normal force acts perpendicular to the surface of the bump and opposes the gravitational force. At the top of the bump, the normal force cancels out the gravitational force. Therefore, the normal force is equal in magnitude to the weight of the person.

Now, let's calculate the apparent weight of the person:

Step 1: Calculate the weight of the person:
W = m * g = 60 kg * 9.8 m/s² = 588 N

Step 2: Calculate the apparent weight:
Since the normal force is equal in magnitude to the weight (W), the apparent weight is also 588 N.

Therefore, the apparent weight of a 60 kg person in your car as you pass over the top of the bump is 588 Newtons.