A sphere submerged in water to the 9-3 o' clock position so that the top half is out of the water. A crate is positioned at the 12 o'clock position. It starts from rest and slides from left to right down to the water. At what angle (theta) does the crate leave the surface of the sphere?
(The surface is frictionless)
its velocity must be greater than the normal component of gravity.
Normal component of gravity: mgCosTheta
energy gained going down: mg*(r-rCostheta)
check that. You can from the energy get the velocity, then mv^2/r