I am having some trouble with some questions and need some help.
A neutron with a mass of 1.68 x10(-27) exponent kg moves from a nuclear reactor with a velocity of 3.22 x10 (3) exponent m/s. What is the Broglie wavelength?
Also, I need to write tge complete electron configuration for a. neon b. sulfur and c.calcium
Thanks. I don't understant this is not that im being lazy
deBroglie wavelength= plancksconstant/momentum
the velocity is low, so relativistic effects can be ignored.
electronic configuration. I don't know if you need to learn how to do it from memory, or just need those atoms.
I will assume you need the algorithm.
http://www.wikihow.com/Write-Electron-Configurations-for-Atoms-of-Any-Element
No problem, I can help you with those questions!
To find the Broglie wavelength of a particle, you can use the De Broglie equation: λ = h / p, where λ represents the wavelength, h is Planck's constant (6.626 x 10^(-34) m^2 kg / s), and p is the momentum of the particle.
To find the momentum, you can use the equation: p = m * v, where p is the momentum, m is the mass of the particle, and v is the velocity.
Let's plug in the values for the question. The mass of the neutron is given as 1.68 x 10^(-27) kg, and the velocity is given as 3.22 x 10^(3) m/s.
So, the momentum of the neutron can be calculated as: p = (1.68 x 10^(-27) kg) * (3.22 x 10^(3) m/s).
Once you have the value for the momentum, you can use that to find the wavelength by plugging it into the De Broglie equation: λ = (6.626 x 10^(-34) m^2 kg / s) / (momentum value).
Solving this equation will give you the value of the Broglie wavelength for the neutron in meters.
Regarding electron configurations, let's go through them one by one:
a. Neon: The atomic number of neon is 10. Therefore, it has 10 electrons. The electron configuration for neon is: 1s^2 2s^2 2p^6.
b. Sulfur: The atomic number of sulfur is 16, meaning it has 16 electrons. The electron configuration for sulfur is: 1s^2 2s^2 2p^6 3s^2 3p^4.
c. Calcium: The atomic number of calcium is 20, so it has 20 electrons. The electron configuration for calcium is: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2.
I hope this helps! If you have any further questions, feel free to ask.