two tuned forks are struck at the same time. one tuned fork has a frequency of 20 hz while the second tuned fork has a frequency of 226 hz. how many beats will result?
226-20=??
http://hyperphysics.phy-astr.gsu.edu/hbase/Sound/beat.html
actually, it depends on what you mean by beats. In this case, one will hear the sum (246) and the difference frequencies (206), as well as the 226hz. Most will never hear the 20hz, but some can.
Normally, mixing near frequencies, we mean by beat the difference of the frequencies, but in reality, one gets the sum and the difference.
To determine the number of beats that will result from two tuned forks with different frequencies, you need to calculate the difference in their frequencies. The number of beats per second is equal to the absolute value of the difference in frequencies.
In this case, subtracting the frequency of the first fork (20 Hz) from the frequency of the second fork (226 Hz) gives us a difference of 206 Hz. Since beats are a measure of the oscillations per second, the number of beats resulting from these two tuned forks is 206 beats per second.
Therefore, striking the two tuned forks with frequencies of 20 Hz and 226 Hz simultaneously will result in 206 beats per second.