You have a stock solution of 15.0 M NH3 . How many milliliters of this solution should you dilute to make 1200ml of 0.280 M NH3?
If you take a 15.0ml- portion of the stock solution and dilute it to a total volume of 0.600 L , what will be the concentration of the final solution?
This is a two part question thanks!
1/60
To determine how many milliliters of the 15.0 M NH3 solution should be diluted to make 1200 ml of 0.280 M NH3, we can use the concept of dilution formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution (Molarity)
V1 = initial volume of the solution (in this case, the volume of the stock solution to be diluted)
C2 = final concentration of the solution (Molarity)
V2 = final volume of the solution (in this case, the desired volume of the diluted solution)
Let's calculate the volume of the stock solution (V1) using the given values:
C1 = 15.0 M
V1 (stock solution volume) = ?
C2 = 0.280 M
V2 (diluted solution volume) = 1200 ml = 1.200 L (converted to liters)
Using the dilution formula:
15.0 M (V1) = 0.280 M (1.200 L)
Now, solve for V1:
V1 = (0.280 M * 1.200 L) / 15.0 M
V1 = 0.0224 L
To convert this volume to milliliters, multiply by 1000:
V1 = 0.0224 L * 1000 ml/L
V1 = 22.4 ml
Therefore, you need to dilute 22.4 milliliters of the 15.0 M NH3 solution to make 1200 ml of 0.280 M NH3.
Now, let's move on to the second part of the question.
If you take a 15.0 ml portion of the stock solution and dilute it to a total volume of 0.600 L, we can determine the concentration of the final solution using the same dilution formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution (Molarity)
V1 = initial volume of the solution (in this case, the volume of the stock solution)
C2 = final concentration of the solution (Molarity)
V2 = final volume of the solution (in this case, the total volume of the diluted solution)
Let's calculate the final concentration (C2) using the given values:
C1 = 15.0 M
V1 (volume of stock solution) = 15.0 ml = 0.015 L (converted to liters)
C2 (final concentration) = ?
V2 (total volume of diluted solution) = 0.600 L
Using the dilution formula:
15.0 M (0.015 L) = C2 (0.600 L)
Now, solve for C2:
C2 = (15.0 M * 0.015 L) / 0.600 L
C2 = 0.375 M
Therefore, the concentration of the final solution is 0.375 M NH3.