A snowball is thrown horizontally with a speed of 23.9 m/s from the top of a campus building. It takes the snowball 1.91 sec to travel from the top of the building to the parking lot below. How tall is the building?
h=1/2 g (1.91)^2
If I was to need to find the range of the snowball how would I go about doing that
?
To find the height of the building, we can use the equation of motion for an object traveling horizontally with a constant velocity:
Distance = Speed × Time
In this case, the speed is the horizontal velocity at which the snowball was thrown, and the time is the time it takes for the snowball to reach the parking lot.
Given:
Horizontal speed (velocity) of the snowball, v = 23.9 m/s
Time taken by the snowball to reach the parking lot, t = 1.91 sec
Using the equation of motion, we have:
Distance = Speed × Time
Substituting the given values:
Height of the building = 23.9 m/s × 1.91 sec
Calculating the height:
Height = 45.649 m
Therefore, the height of the building is approximately 45.649 meters.