I did a lab where we had to determine the iron content in ore...i am confused about the reactions that occured during the reaction...i need reactions for the following...


1) The samples were treated with 6M HCl until all the iron ore dissolved.Assuming all of the ore is in the form Fe2O3m, what is the balanced equation for this process?

What I have is..

Fe2O3(s) + 6HCl (aq) --> 2FeCl3(aq) + 3H2O (l)

2) Samples were then treated with Zn metal according to the following balanced chemical equation...

i have the following, but am unsure if it is correct and if it is i am unsure how to balance it (charges..)

2FeCl3(aq) + 3Zn(s)--> 3ZnCl2(aq) + 2Fe^3+

3) Immediately prior to titration, any excess zinc was removed by treatment with 3M H2SO4 according to the following balanced chemical equation:

I am not sure how to go about writing this equation....

Any help or guidance would be greatly appreciated!!

The 2nd reaction is

2FeCl3(aq) + 3Zn(s)--> 3ZnCl2(aq) + 2Fe(s)
The excess zinc removal reaction is
Zn(s) + H2SO4(aq) --> ZnSO4(aq) + H2(g)

Sure! I can help you with that. Let's go through each of the reactions step by step.

1) The reaction between Fe2O3 and 6M HCl:

Fe2O3(s) + 6HCl(aq) → 2FeCl3(aq) + 3H2O(l)

This equation is correct. Fe2O3, which is iron(III) oxide, reacts with 6HCl (hydrochloric acid) to form 2FeCl3 (ferric chloride) and 3H2O (water).

2) The reaction between 2FeCl3 and 3Zn:

2FeCl3(aq) + 3Zn(s) → 3ZnCl2(aq) + 2Fe(s)

The equation you provided is almost correct. However, the product should be 2Fe(s) instead of 2Fe^3+. This reaction involves the reduction of iron(III) ions to iron metal by zinc. The zinc is oxidized to Zn^2+ ions, forming ZnCl2 (zinc chloride) as the product.

3) The reaction between any excess zinc and 3M H2SO4:

Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)

In this reaction, zinc reacts with sulfuric acid (H2SO4) to form zinc sulfate (ZnSO4) and hydrogen gas (H2). This reaction helps remove any excess zinc before the titration step.

I hope this clarifies the reactions for you. If you have any more questions, feel free to ask!