the total cost for a school bus rental is 350$/day. Each bus holds 60 students. Find the cost (c) of renting the school bus as a function of the number of students going on a trip (n).
My answer:
I have come up with relating the 350$ to n/60 but i am stuck on where to go from here. Can somebody help me? Thanks.
If n is the number of students going, the cost per student per day is $350/n.
If the bus is full, the cost per student is 350/60 = $5.83.
The function is undefined for n>60.
Therefore
f(n) = $350/n, 1<n<59
f(n=60) = $5.83
f(n>60) = undefined
Thank you very much. I wrote my question incorrectly. It should be the cost of renting buses (plural). Would that be something like 350 times n/60?
To find the cost (c) of renting the school bus as a function of the number of students going on a trip (n), you can start by breaking down the problem into different scenarios.
Given:
- The total cost for a school bus rental is $350/day.
- Each bus holds 60 students.
Since the cost is dependent on the number of students going on the trip, you could calculate the number of buses required based on the number of students.
To find the number of buses (b) needed:
- Divide the number of students (n) by the capacity of each bus (60): b = n/60.
- Round the result up to the nearest whole number, as you cannot have a fraction of a bus. Let's call this value "x".
Now, the number of buses required can be rewritten as:
- If n is a multiple of 60, b = n/60.
- If n is not a multiple of 60, b = (n/60) + 1.
To calculate the cost (c) of renting the school bus for a trip with "n" students:
- If n is a multiple of 60, c = 350 * x.
- If n is not a multiple of 60, c = 350 * (x + 1).
In conclusion, the cost (c) of renting the school bus as a function of the number of students going on a trip (n) is:
- If n is a multiple of 60, c = 350 * (n/60).
- If n is not a multiple of 60, c = 350 * ((n/60) + 1).