I don't know how to solve 12x(2)-15x=0 using the quadratic equation ax+bx+c=0 with this question I am unsure of what a, b and c are supposed to be, therefore I do not know how to solve this! Please help!
Solve the quadratic equation. 3x^2-15x+18=0 I know that the formula to quadratic equation is x=-b+and-(square root)b^2-4ac divided by 2a. I know that a=3, b=-15 and c=18, then subsitute in and get two answers, my problem is that I
Use the quadratic formula to solve each of the following quadratic equations... 1. 2x^2-5x=3 2. 3x^2-2x+1=0 Rearrange the equation in quadratic formula form. 2x^2 -5x -3 = 0 Then use the formula. Tell me what you don't understand
(24x^3-54x^2-15x)/(6x^2-15x) i don't factor number from whole equation way i do it is find number that add to give me -54 and multiply to give -360. the number i get -60 and +6. so i do this: 24x^3-60x+6x-15x i factor this further
could you walk-through the steps to solving this problem because I am stuck; 3x-5(3x-7)=2(x+9)+45 Let me know if you have a question in any step. 3x-5(3x-7)=2(x+9)+45 3x-15x+35= 2x+18+45 -12x+35 = 2x+63 -35 -35 -12x= 2x +63-35