I don't know how to solve 12x(2)-15x=0 using the quadratic equation ax+bx+c=0 with this question I am unsure of what a, b and c are supposed to be, therefore I do not know how to solve this! Please help!
The standard quadratic equation form is
ax^2 + bx + c = 0
and your equation is, if your (2) is supposed to be an exponent,
12x^2 -15x = 0
Therefore a = 12, b = -15 and c = 0
You have reduced your equaion to
4x^2 -5x = 0,
so using a=4, b=-5 and c=0 would give you the same results for x.
You should get x = 0 and x = 5/4 as the solutions, using the quadratic equation
x = [-b +/-sqrt(b^2 -4ac)]/(2a)
To solve the equation 12x(2)-15x=0 using the quadratic equation ax+bx+c=0, we need to rewrite the equation in the standard quadratic equation form.
First, let's rearrange the equation to have it in the form ax^2 + bx + c = 0. In this case, we have:
12x^2 - 15x = 0
Now, compare this equation to the standard form:
ax^2 + bx + c = 0
By comparing, you can see that a (the coefficient of x^2) is 12, b (the coefficient of x) is -15, and c (the constant term) is 0.
Now that we have identified the values of a, b, and c, we can use the quadratic formula to find the roots of the equation. The quadratic formula states that for any quadratic equation in the form ax^2 + bx + c = 0, the roots can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / 2a
Let's substitute the values of a, b, and c into the quadratic formula for our equation:
x = (-(-15) ± √((-15)^2 - 4(12)(0))) / (2(12))
Simplifying further, we have:
x = (15 ± √(225)) / 24
Since the square root of 225 is 15, we can simplify the equation to:
x = (15 ± 15) / 24
Now, we have two possible solutions:
1. x = (15 + 15) / 24 = 30 / 24 = 5/4
2. x = (15 - 15) / 24 = 0 / 24 = 0
Therefore, the solutions to the equation 12x(2)-15x=0 are x = 5/4 and x = 0.