what is the force required to start moving a 25kg box across a concrete floor with a coefficient of static friction of .65?
The force required (in newtons) is μmg where m=mass of box, μ=coefficient of friction, and g=acceleration due to gravity on earth = 9.8 m/s².
Well, let's put this problem in context. Moving a 25kg box across a concrete floor? That sounds like quite the workout! Now, to determine the force required to start moving this box, we need to consider the coefficient of static friction.
Think of the coefficient of static friction as the "stickiness" between the box and the floor. In this case, with a coefficient of 0.65, it's like the box is saying, "Hey, I really like it here, do I have to move?"
But fear not! To overcome this static friction and get the box moving, we need to exert a force greater than the friction force. The formula for friction is F = μN, where F is the friction force, μ is the coefficient of static friction, and N is the normal force (which is equal to the weight of the box).
So, the force required to start moving the box is:
F = (0.65) * (25kg * 9.8m/s^2)
Now, after doing the calculations, the force required is approximately 159.25 Newtons. But remember, this is just the amount of force required to overcome static friction and start moving the box. Once it's in motion, you'll need less force to keep it going.
So, lace up those sneakers and get ready to push, because that box isn't going to move itself!
To determine the force required to start moving a 25kg box across a concrete floor with a coefficient of static friction of 0.65, you can follow these steps:
Step 1: Identify the equation for static friction:
The equation for static friction is given by:
\( F_{\text{{friction}}} = \mu_s \times F_{\text{{normal}}} \)
where:
\( F_{\text{{friction}}} \) is the static frictional force,
\( \mu_s \) is the coefficient of static friction, and
\( F_{\text{{normal}}} \) is the normal force exerted on the box.
Step 2: Calculate the normal force:
The normal force is equal to the weight of the box. In this case, the weight can be calculated using the equation:
\( F_{\text{{gravity}}} = m \times g \)
where:
\( F_{\text{{gravity}}} \) is the weight of the box,
\( m \) is the mass of the box, and
\( g \) is the acceleration due to gravity (approximately 9.8 m/s²).
Substituting the given values, we have:
\( F_{\text{{gravity}}} = 25 \, \text{{kg}} \times 9.8 \, \text{{m/s²}} \)
Step 3: Calculate the static frictional force:
Finally, substitute the values of the coefficient of static friction (\( \mu_s \)) and the normal force (\( F_{\text{{normal}}} \)) into the equation for static friction:
\( F_{\text{{friction}}} = 0.65 \times F_{\text{{normal}}} \)
Combine the steps, and use the given values to solve the problem.
To calculate the force required to start moving a box across a concrete floor, we need to consider the coefficient of static friction. The formula to calculate the force of static friction is:
F(static friction) = coefficient of static friction * normal force
The normal force can be calculated using the formula:
Normal force = mass * gravity
where mass is the mass of the box (25 kg) and gravity is the acceleration due to gravity (approximately 9.8 m/s^2).
Plugging in the values, we have:
Normal force = 25 kg * 9.8 m/s^2 = 245 N
Now we can calculate the force of static friction:
F(static friction) = 0.65 * 245 N
F(static friction) ≈ 159.25 N
Therefore, approximately 159.25 Newtons of force is required to start moving a 25 kg box across a concrete floor with a coefficient of static friction of 0.65.