A baseball has a mass of 0.15 kg. A pitcher throws a 40 m/sec fastball which is caught by the catcher. What is the change in momentum of the ball?
What is M*changeinvelocity?
so .15 x 40? because the initial velociy equals zero?
yes. include units.
The next part of the questions says What is the impulse on the catcher’s mitt?
to find impulse do I use the equation
m(vf-vi)
with vf = 0m/s and vi= 40m/s
yes
To calculate the change in momentum of the ball, you need to know its initial momentum and its final momentum. The momentum of an object is calculated by multiplying its mass by its velocity.
Given that the mass of the baseball is 0.15 kg and the initial velocity is 40 m/s, we can calculate the initial momentum by multiplying these two values:
Initial momentum = mass × initial velocity
Initial momentum = 0.15 kg × 40 m/s
Next, we need to determine the final momentum. Since the baseball is caught by the catcher, its final velocity is zero m/s. Therefore, the final momentum is:
Final momentum = mass × final velocity
Final momentum = 0.15 kg × 0 m/s
Now, to find the change in momentum, we subtract the final momentum from the initial momentum:
Change in momentum = final momentum - initial momentum
Change in momentum = (0.15 kg × 0 m/s) - (0.15 kg × 40 m/s)
Since the final velocity is zero, the final momentum is zero:
Change in momentum = 0 - (0.15 kg × 40 m/s)
Change in momentum = -6 kg·m/s
The change in momentum of the ball is -6 kg·m/s, indicating that the direction of the momentum has reversed from initial to final.