WORD PROBLEM

GOING SKIING. LEON DROVE 270 MILES TO THE LODGE IN THE SAME TIME AS PAT DROVE 330 MILES TO THE LODGE. IF PAT DROVE 10 MILES PER HOUR FASTER THAN LEON, THEN HOW FAST DID EACH OF THEM DRIVE?

I REALLY NEED HELP ON THIS ONE. PLEASE! IF YOU CAN SHOW THE WORK WILL BE GREAT I THINK I WILL UNDERSTAND IT BETTER THAN JUST SEEING THE ANSWER. tHINKS


Leon's travel time = (270 miles/V1)Pat's travel time = (330 miles/V2)
The times are equal.

V1 = Leon's speed and V2 = Pat's speed
V2 = V1 + 10

270/V1 = 330/(V1 + 10)
(V1 +10)/V1 = 330/270 = 11/9
1 + (10/V1) = 11/9
10/V1 = 2/9
V1 = 45 mph
V2 = 55 mph


. Leon drove 270 miles to the lodge in the same time as Pat drove 330 miles to lodge. If Pat drove 10miles per hour faster than Leon, then how fast did each of them drive?
b.Why are there usually two solutions in quadratic equations?

c.under what situation would one or more solutions of a rational equation be unacceptable?


I think pat was the faster one that's my inser


I have looked at this question several times and it seems as though there is missing information to solve this problem.Without time, you can not rate speed.Yes it tells the difference in milage and speed difference but I bellieve this question has no answer without a key pice of information such as departure and arival time of atleast one person. I have seen many people post questions such as these and try to throw you off to make you thump your gray matter so you will assume there is a answer, when in all reality there is none.But perhaps I am just missing somthing and have not approached this question in the right light but the way I see it there are unlimited answers to this question since there ahs been no reffrence point given for time elapsed.If there is a correct answer,I would be very anxious to here it so I could figure out the formula used to calculate this. Good luck!!!

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asked by leleirvin

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