if 0.225 mol of tin combined with 0.450 mol sulfur, what is the empirical formula of the tin sulfide product?
moles Sn = 0.225
moles S = 0.450
ratio. divide by smallest number to make it 1.00
Sn = 0.225/0.225 = 1.00
S = 0.450/0.225 = 2.00
empirical formula is Sn1S2. Of course the 1 is not needed so it is SnS2.
To determine the empirical formula of the tin sulfide product, we need to find the ratio of the elements present in the compound.
1. Determine the moles of tin and sulfur:
Tin: 0.225 mol
Sulfur: 0.450 mol
2. Divide both the moles by the smallest value to get the simplified ratio:
Tin: 0.225 mol ÷ 0.225 mol = 1 mol
Sulfur: 0.450 mol ÷ 0.225 mol = 2 mol
Simplified ratio: 1:2
3. Write the empirical formula using the elemental symbols and the ratio:
The empirical formula of the tin sulfide product is SnS2.
To determine the empirical formula of the tin sulfide product, we need to find the ratio of tin to sulfur atoms in the compound.
1. Start by noting the number of moles of tin (Sn) and sulfur (S) provided: 0.225 mol of tin and 0.450 mol of sulfur.
2. Divide both values by the smallest number to obtain the simplest whole number ratio.
- 0.225 mol tin ÷ 0.225 mol sulfur = 1.0
- 0.450 mol sulfur ÷ 0.225 mol sulfur = 2.0
3. The ratio is now 1:2.
4. Write the empirical formula using the ratio as subscripts: SnS₂.
Therefore, the empirical formula of the tin sulfide product is SnS₂.